So U Think U R Very Good At Maths...?

[Arun 795]

Three is equal to four....

Theorem: 3=4

Proof:

Suppose:

a + b = c

This can also be written as:

4a - 3a + 4b - 3b = 4c - 3c

After reorganizing:

4a + 4b - 4c = 3a + 3b - 3c

Take the constants out of the brackets:

4 * (a+b-c) = 3 * (a+b-c)

Remove the same term left and right:

4 = 3

Four is equal to five

Theorem: 4 = 5

Proof:

-20 = -20

16 - 36 = 25 - 45

4^2 - 9*4 = 5^2 - 9*5

4^2 - 9*4 + 81/4 = 5^2 - 9*5 + 81/4

(4 - 9/2)^2 = (5 - 9/2)^2

4 - 9/2 = 5 - 9/2

4 = 5

Howzat ?!?

[Ramchi 0]

Good one

You may all know this:

With one strike you need to solve this equation:

5+5 = 545

By adjusting only one digit in the following equation you need to solve:

102 - 2 = 98

[Puneet 0]

4 * (a+b-c) = 3 * (a+b-c)

This is a fallacy. Since a+b=c, a+b-c=0. The above equality holds only because both the sides are zero. And when a multiplication by zero term is involved, you cannot equate the coefficient of the terms. This would amount to saying 1*0 = 0, and also 10000000000* 0 = 0 hence, 1 = 10000000000 (or whatever).

(4 - 9/2)^2 = (5 - 9/2)^2

4 - 9/2 = 5 - 9/2

4 = 5

(4 - 9/2)^2 = (5 - 9/2)^2 = 0.25

Square roots of 0.25 are +/- 0.5

Similarly, square roots of (4 - 9/2)^2 are +/- (4 - 9/2) and (5 - 9/2)^2 are = +/-(5 - 9/2)^2.

4-9/2 = -0.5 and 5-/2=0.5.

You are equating the wrong roots. Correct way would be -(4-9/2)=(5-9/2) or (4-9/2)=-(5-9/2)

Expanding the brackets in one of the above

-4 + 9/2 = 5 -9/2, perfectly correct and now you cannot cancel out 9/2, hence 4 is not equal to 5.

[ashoksoft 83]

IIT brains at work

[supernova 47]

really a good theorm and a nice reply.........i mailed this to all my friends

[abhay 0]

hmm good one

Edited December 18, 2005 by abhay

[rEdshiFt 1]

sharp, puneet

[Puneet 0]

IIT brains at work

We used to solve these kinda things while I was in class XI. Long ago, and I was not an IITian then

sharp, puneet

Thanks.

[ashoksoft 83]

wonder what in puneet is sharp

[ani_meher 42]

Good one

You may all know this:

With one strike you need to solve this equation:

5+5 = 545

By adjusting only one digit in the following equation you need to solve:

102 - 2 = 98

The answer of first one is, draw one verticle line to the top left of + sign, so it becomes 4, like

it is _|_ , draw a line to make it |_|_ , ie 4. (pls ignore the 'i's in next line. It's not taking spaces.

i i i i i | i i i i i i i i i i i i i i i i i i i i i i i i |

As for the second one, I guess the 'adjusting' is making the 2 as 4. ie 102 - 4 = 98. But I am not sure about this one.

Edited December 20, 2005 by ani_meher

[SexyGurl 0]

Good one

You may all know this:

With one strike you need to solve this equation:

5+5 = 545

By adjusting only one digit in the following equation you need to solve:

102 - 2 = 98

The answer of first one is, draw one verticle line to the top left of + sign, so it becomes 4, like

it is _|_ , draw a line to make it |_|_ , ie 4. (pls ignore the 'i's in next line. It's not taking spaces.

i i i i i | i i i i i i i i i i i i i i i i i i i i i i i i |

As for the second one, I guess the 'adjusting' is making the 2 as 4. ie 102 - 4 = 98. But I am not sure about this one.

I think, he meant just moving around the digits, not changing a digit... so it's very likely:

10^2 - 2 = 98 (i.e. just move the 2 in 102 to the exponent).

[ani_meher 42]

I think, he meant just moving around the digits, not changing a digit... so it's very likely:

10^2 - 2 = 98 (i.e. just move the 2 in 102 to the exponent).

Yes, this seems to be the right answer.

[Ramchi 0]

SexyGurl & Ani Mehar both are correct!!!! Keep it up!